The Weil Pairing

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3 Responses to The Weil Pairing

  1. X says:

    Hello Jim,

    Is it clear that the Weil Pairing is well-defined? (regardless of the choice of “some X \in E”)

  2. Jim Stankewicz says:

    Oh yes. The point is that g_Q(X + R) = g_Q(X) for any X \in E, and we can see that because they have the same divisor as functions of X.

  3. Pingback: Symposium “Abel Prize 2010” « Disquisitiones Mathematicae

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